The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45,426.16 and 91.0 S cm — NEET Chemistry Past Papers Chemistry Question
Question
The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45,426.16 and 91.0 S cm2 mol–1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer. (A) 201.28 S cm2 mol–1 (B) 390.71 S cm2 mol–1 (C) 698.28 S cm2 mol–1 (D) 540.48 S cm2 mol–1
Answer: A
💡 Solution & Explanation
¥ Lm (NaCl) = 126.45 Scm2 mol–1 ¥ Lm (HCl) = 426.16 Scm2 mol–1 ¥ L = 3 m(CH COONa) 91 Scm2 mol–1 \ ¥ ¥ ¥ ¥ L = L + L L 3 3 m(CH COOH) m(CH COONa) m(HCl) m(NaCl) – = 91 + 426.16 – 126.45 = 391.72 Scm2 mol–1 2 Final NEET(UG)-2021 Exam/12-09-2021
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