For a given chemical reaction Concentration of C changes from 10 mmol dm to 20 mmol dm in 10 seconds — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

**Step 1: Find the rate of appearance of D** Given: Rate of appearance of D = 9 mmol dm⁻³ s⁻¹ **Step 2: Establish the relationship between rates** Given relationships: - Rate of appearance of D = 1.5 × (rate of disappearance of B) - Rate of disappearance of B = 2 × (rate of disappearance of A) Therefore: - Rate of disappearance of B = 9/1.5 = 6 mmol dm⁻³ s⁻¹ - Rate of disappearance of A = 6/2 = 3 mmol dm⁻³ s⁻¹ **Step 3: Calculate rate of appearance of C** Change in concentration of C = 20 - 10 = 10 mmol dm⁻³ Time = 10 seconds Rate of appearance of C = 10/10 = 1 mmol dm⁻³ s⁻¹ **Step 4: Determine the rate of reaction** For the reaction: aA + bB → cC + dD The rate of reaction is defined as: Rate = |−ΔA|/a = |−ΔB|/b = |ΔC|/c = |ΔD|/d Using the rate of appearance of C (which is the simplest value): Rate of reaction = 1 mmol dm⁻³ s⁻¹ Therefore, the answer is **1.00** mmol dm⁻³ s⁻¹