Pb(AcO)2 + H2S -> PbS↓ + 2AcOH — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Lead(II) acetate is a highly soluble salt in water. Step 2: Passing hydrogen sulfide gas (H2S) through the solution precipitates highly insoluble black lead(II) sulfide, PbS↓. Step 3: Since a precipitate is formed from soluble starting materials, this is a precipitate formation reaction (type A), corresponding to option (a).