Consider the following conversions : (i) O(g) + e- - O-(g), \Delta H1 ; (ii) F(g) + e- - F-(g), \Delta H2 ; (iii) Cl(g) + e- - Cl-(g), \Delta H3 ; (iv) O-(g) + e- - O2-(g), \Delta H4. That accordi

Question

Consider the following conversions : (i) O(g) + e- -> O-(g), \Delta H1 ; (ii) F(g) + e- -> F-(g), \Delta H2 ; (iii) Cl(g) + e- -> Cl-(g), \Delta H3 ; (iv) O-(g) + e- -> O2-(g), \Delta H4. That according to given information the incorrect statement is :

Prashant Kotian · Accepted Answer

Correct answer: D. Step 1: Note the positions of the elements: O and Se are in Group 16 (Periods 2 and 4), C is in Group 14 (Period 2), and S is in Group 16 (Period 3). Step 2: Atomic radius increases down a group (O < S < Se) and decreases across a period from left to right (so O < C). Second-period elements (O and C) are significantly smaller than third-period (S) and fourth-period (Se) elements. Step 3: Combining these trends, the correct increasing order of atomic radius is O < C < S < Se.

💡 Solution & Explanation

Practice 22,000+ questions like this