See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 (Identify the compound type): The structure shown is an ester, recognizable by the -C(=O)-O- linkage connecting two carbon chains. Step 2 (Identify the acid-derived portion): The carbonyl side (left of the oxygen) contains a four-carbon chain: CH3-CH2-CH2-C(=O)-, which comes from butanoic acid. The acyl group name is therefore 'butanoate.' Step 3 (Identify the alcohol-derived portion): The oxygen is connected on the right to -CH2-CH(CH3)2, which is a three-carbon unit with a methyl branch on the second carbon. This fragment derives from 2-methyl-1-propanol (isobutanol). The alkyl group name is '2-methylpropyl.' Step 4 (Combine the name): In IUPAC ester nomenclature, the alcohol-derived alkyl group is named first, followed by the acid-derived name ending in '-ate.' Combining: '2-methylpropyl' + 'butanoate' = 2-methylpropyl butanoate. Step 5 (Verify): The carbonyl carbon plus three additional carbons gives butanoic acid (4 carbons total); the oxygen-linked carbon is a -CH2- attached to an isobutyl framework, confirming 2-methylpropyl. No other interpretations are consistent with the structure shown. Therefore, the correct answer is 2-methylpropyl butanoate.