The dye acriflavine when dissolved in water has its maximum light absorption at 4530 Å and has maximum fluorescence emission at 5080 Å. The number of fluorescence quanta is about 53% of the number of

Question

The dye acriflavine when dissolved in water has its maximum light absorption at 4530 Å and has maximum fluorescence emission at 5080 Å. The number of fluorescence quanta is about 53% of the number of absorbed quanta. What percentage of absorbed light energy is emitted as fluorescence?

Prashant Kotian · Accepted Answer

Correct answer: B. % energy emitted = (N_flu/N_abs) × (λ_abs/λ_flu) × 100% = 0.53 × (4530/5080) × 100% ≈ 47%.

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