See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

P  1, 3; Q  2; R  4; S  2     2 0 l m ln 1 2mcos x m dx              2 2 0 0 l m ln 1 2mcosx m dx ln 1 2mcos x m dx                 2 0 ln 1 2mcos x m dx l m           l m l m    …..(1) Also       2 4 0 l m l m ln 1 2m cos2x m dx        Put 2x = t       2 l m l m l m     ….(2)         2 2 l m 2l m l m 2. l m    AITS-FT-III (Paper-1)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12