See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

 15 f 1   Hence N =      14 13 2 3 14 15 15 1 1 1 1       For More Material Join: @JEEAdvanced_2024 AITS-CRT-IV (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11