Two moles of an ideal monoatomic gas is heated from 27°C to 627°C, reversibly and isochorically. The — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Isochoric heating: Δ S = n * $C_v$ * ln(T2/T1). For monoatomic gas $C_v$ = 1.5 R. Given n = 2, T1 = 300 K, T2 = 900 K. Δ S = 2 * 1.5 R * ln(900/300) = 3R * ln 3. Entropy increases by 3R ln 3.