Total number of electron present in (*) molecular orbitals of O2 , O and O is_______. — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

O2(16e)      2 2 * * 1s 1s 2s 2s              1 2 * * 2p 2p 2p 2p 2p ,               Number of e– present in   * of O 2   Number of e– present in   * of O 1    Number of e– present in   * – of O 3   So total e– in   *  = 2 + 1 + 3 = 6