83 g of ethylene glycol dis β JEE Mains Chemistry Past Papers Chemistry Question
Question
83 g of ethylene glycol dis
Answer: .
π‘ Solution & Explanation
οTΖ = iKΖ Γ m = 62 83 . 1 ο΄ ο΄ ο΄ ο΄ οTΖ = 3.98 So, freezing point of solution = 273 β 3.98 = 269.02 = 269 K | JEE MAIN-2021 | DATE : 26-08-2021 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10
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