83 g of ethylene glycol dis — JEE Mains Chemistry Past Papers Chemistry Question
Question
83 g of ethylene glycol dis
Answer: .
💡 Solution & Explanation
Tƒ = iKƒ × m = 62 83 . 1 Tƒ = 3.98 So, freezing point of solution = 273 – 3.98 = 269.02 = 269 K | JEE MAIN-2021 | DATE : 26-08-2021 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes