See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

48. 5 Sol. At 3 th 4 of the equivalence point, For More Material Join: @JEEAdvanced_2025 AITS-FT-V-PCM(Sol.)-JEE(Main)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11     b 3 / 4 pOH pK log 1/ 4    b pOH pK log 3   pH = 14 – pOH  b 14 pK log 3    b b 14 pK 9 pK 5      b pK 5   5 b K 10   n 5  