The elevation in boiling point, when 13.44 g of freshly prepared CuCl2 are added to one kg of water, is (Some useful data: of water = 0.52 K-kg/mol; molecular weight of CuCl2 = 134.4)

Question

The elevation in boiling point, when 13.44 g of freshly prepared CuCl2 are added to one kg of water, is (Some useful data: $K_b$ of water = 0.52 K-kg/mol; molecular weight of CuCl2 = 134.4)

Prashant Kotian · Accepted Answer

Correct answer: C. Moles of CuCl2 = 13.44 / 134.4 = 0.10 mol. Molality m = 0.10 m. CuCl2 → 3 ions, i = 3. ΔT_b = 3 * 0.52 * 0.10 = 0.156 K ≈ 0.16 K.

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