Lowest Oxidation number of an atom in a compound A2B is -2. The number of an electron in its valence — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

A2B  2A+ + B– 2, B-2 has complete octet in its di- anionic form, thus in its atomic state it has 6 electrons in its valence shell. As it has negative charge, it has acquired two electrons to complete its octet.