How many geometrical isomers and stereoisomers are possible for [Pt(NO2)(NH3)(NH2OH)(Py)]^+ and [Pt( — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Step 1: For the square planar complex [Pt(NO2)(NH3)(NH2OH)(Py)]^+ (type [MABCD]), there are exactly 3 geometrical isomers. Since square planar complexes are planar, they are achiral and have no enantiomeric pairs, meaning they have exactly 3 stereoisomers. Step 2: For the octahedral complex [Pt(Br)(Cl)(I)(NO2)(NH3)(Py)] (type [MABCDEF] with six different ligands), there are 15 geometrical isomers. Step 3: Because every one of these 15 geometrical isomers lacks a plane of symmetry, each is chiral and exists as a pair of d- and l- enantiomers. This yields 15 * 2 = 30 stereoisomers. Therefore, the answer is 3 and 30, corresponding to option (b).