Two carbon discs, 1.0 g each, are 1.0 cm apart have equal and opposite charges. If force of attraction between them is 10^-5 N, the ratio of excess electrons to the total atoms on the negatively charg

Question

Two carbon discs, 1.0 g each, are 1.0 cm apart have equal and opposite charges. If force of attraction between them is 10^-5 N, the ratio of excess electrons to the total atoms on the negatively charged disc is

Prashant Kotian · Accepted Answer

Correct answer: B. F = kq²/r² => q = 3.33 × 10^-10 C. n = q/e = 2.08 × 10^9 electrons. Total atoms = N_A/12 = 5.0 × 10^22. Ratio = 2.08 × 10^9 / 5.0 × 10^22 ≈ 10^-12 : 2.4.

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