See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

4 3 3 4 2 2 20 4 20 4 P HNO H PO NO H O     3 4 3 4 100 0.1 . 2 . . 5 2 m molesof NaOH m molesof H PO m moles H PO       3 20 m.molesof HNO = ×5=25 4 Volume of 3 HNO =25ml