Correct answer: 2. 3 1 4 3 2 2 P NaOH PH NaH PO          3 1 2   

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 2

💡 Solution & Explanation

3 1 4 3 2 2 P NaOH PH NaH PO          3 1 2   

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