See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   2 o o o o 2NO g Cl g 2NOCl g Initial partial pressure P P 0 Partial pressure at equilibrium P 2x P x 2x      Ptotal at equilibrium o o P 2x P x 2x      o 2P x 1   Given,   o 1 2x P x 2   o o 4x P x, P 5x    o 2P x 1    2 5x x 1    9x = 1 1 x 9  o NO P P 2x 5x 2x 3x      2 o Cl P P x 5x x 4x      NOCl P 2x        2 2 NOCl P 2 NO Cl P K P P       2 P 2 2x 1 K 9x 3x 4x    P 1 K 1 1 9 9    KP for the reaction is 1 1atm.