See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

The instantaneous magnetic flux through the loop is B BAcos    Since,  = t, therefore, B BAcos t    From Faraday’s law, equation B d d e BAcos t dt dt         or e BA sin t    The induced current is e BA I sin t R R           The amplitude of induced current (in mA) = BA R = 1