The expression for compressibility factor for one mole of a van der Waal's gas at Boyle temperature — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

at boyle's temperature, a/rt = b. the van der waals equation can be rearranged as z = vm / (vm - b) - a / (rt vm). substituting a/rt = b: z = vm / (vm - b) - b / vm = (vm^2 - b(vm - b)) / (vm(vm - b)) = (vm^2 - bvm + b^2) / (vm(vm - b)) = 1 + b^2 / (vm(vm - b)).