A mixture of and , in a vessel are allowed to effuse out through a small hole at the same temperature. What is the mole fraction of , if the initial rates of effusion are the same for both gases?

Question

A mixture of $CH_4$ and $HBr$, in a vessel are allowed to effuse out through a small hole at the same temperature. What is the mole fraction of $CH_4$, if the initial rates of effusion are the same for both gases?

Prashant Kotian · Accepted Answer

Correct answer: A. equal effusion rate means x_ch4 / √(m_ch4) = x_hbr / √(m_hbr) → x_ch4 / √16 = (1 - x_ch4) / √81 → x_ch4 / 4 = (1 - x_ch4) / 9 → 9x_ch4 = 4 - 4x_ch4 → 13x_ch4 = 4 → x_ch4 = 4/13 = 0.31.

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