JEE Mains Chemistry Past PapershardNUMERICAL

For the thermal decomposition of N2O5(g) at constant volume, the following table can be formed, for JEE Mains Chemistry Past Papers Chemistry Question

Question

For the thermal decomposition of N2O5(g) at constant volume, the following table can be formed, for the reaction mentioned below. 2N2O5(g) 2N2O4(g) + O2(g) Sr. No. Time/s Total pressure/(atm) 0 0.6 100 'x' x = _____ × 10–3 atm [nearest integer] Given : Rate constant for the reaction is 4.606 × 10–2 s–1.

Answer: .

💡 Solution & Explanation

2N2O5(g) 2N2O4(g) + O2(g) Given K = 4.606 × 10–2 sec–1 Ist order : 2N2O5(g) 2N2O4(g) + O2(g) t = 0 : P0 0 t = t : P0–y y y/2 t =  : 0 P0 P0/2 t = 100 min PTotal = P0 + y = P0 + y x = 0.6 + y ; y = 2x – 1.2 K = 1 ln y – P P 0 4.606 × 10–2 = 1 × 2.303 log . x – . 6 .  4.606 × 10–2 = 1 × 2.303 log x – . 6 . = log x – . 6 . 100 (1.8 – 2x) = 0.6 180 – 200 x = 0.6 x = 200 . = 0.897 = 897 × 10–3

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