For the thermal decomposition of N2O5(g) at constant volume, the following table can be formed, for — JEE Mains Chemistry Past Papers Chemistry Question
Question
For the thermal decomposition of N2O5(g) at constant volume, the following table can be formed, for the reaction mentioned below. 2N2O5(g) 2N2O4(g) + O2(g) Sr. No. Time/s Total pressure/(atm) 0 0.6 100 'x' x = _____ × 10–3 atm [nearest integer] Given : Rate constant for the reaction is 4.606 × 10–2 s–1.
💡 Solution & Explanation
2N2O5(g) 2N2O4(g) + O2(g) Given K = 4.606 × 10–2 sec–1 Ist order : 2N2O5(g) 2N2O4(g) + O2(g) t = 0 : P0 0 t = t : P0–y y y/2 t = : 0 P0 P0/2 t = 100 min PTotal = P0 + y = P0 + y x = 0.6 + y ; y = 2x – 1.2 K = 1 ln y – P P 0 4.606 × 10–2 = 1 × 2.303 log . x – . 6 . 4.606 × 10–2 = 1 × 2.303 log x – . 6 . = log x – . 6 . 100 (1.8 – 2x) = 0.6 180 – 200 x = 0.6 x = 200 . = 0.897 = 897 × 10–3