The molality of a 10% (v/v) — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Molarity 10% V V Solvent = CCl4 Solvent = Br2 100 mL has 10mL Br2 & 90 mL CCl4 m = 10 × 3.0 = 32 g n = 32 = 1 mol CCl m = 90 × 1.6 =144 g = 0.144 kg m = . 5 = 1.39 = 139 ×10–2