Compound(A)C8H6O --(NH2OH/HCl)--> B + C; C --(H+)--> D B --(H+)--> E --(i)Boil NaOH, (ii) H+/H2O--> β AITS & Test Series Chemistry Question
Question
Compound(A)C8H6O --(NH2OH/HCl)--> B + C; C --(H+)--> D B --(H+)--> E --(i)Boil NaOH, (ii) H+/H2O--> G(C7H6O2) (white solid) D --(i)KOH, (ii) H+/H2O--> F(C8H7N) --(CH3COCl rapid)--> D (Oil) [B, C, D and E are isomers having molecular formula C8H9NO] Which of the following statement is/are correct regarding above reaction: (A) Compound(A) is an aldehyde and can give (+ ve) Tollen's test (B) Compound (B) and (C) can show geometrical isomerism (C) Compound (A) is an aromatic ketone which having structure [benzene ring]-C(=O)-CH3 (D) Compound (G) is more acidic than CH3COOH

π‘ Solution & Explanation
25. ACD Square planar complex can show enantiomerism. Pt CH CH C6H5 H2N NH2 NH2 C6H5 CH2 C NH2 CH3 CH3 Pt CH CH C6H5 NH2 NH2 H2N C6H5 CH2 C NH2 CH3 CH3 2+ 2+ Mn O O O Oο Tetrahaedral, d3s hybridisation