When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of a — Surface Chemistry Chemistry Question

💡 Solution & Explanation

**Step 1: Calculate initial moles of acetic acid** Initial moles = Molarity × Volume (L) Initial moles = 0.2 M × 0.2 L = 0.04 mol **Step 2: Calculate final moles of acetic acid** Final moles = 0.1 M × 0.2 L = 0.02 mol **Step 3: Calculate moles of acetic acid adsorbed** Moles adsorbed = Initial moles − Final moles Moles adsorbed = 0.04 − 0.02 = 0.02 mol **Step 4: Convert moles adsorbed to mass** Molar mass of acetic acid (CH₃COOH) = 12(2) + 1(4) + 16(2) = 60 g/mol Mass adsorbed = 0.02 mol × 60 g/mol = 1.2 g **Step 5: Calculate mass adsorbed per gram of carbon** Mass per gram of carbon = Total mass adsorbed ÷ Mass of carbon Mass per gram of carbon = 1.2 g ÷ 0.6 g = 2 g/g Therefore, the answer is 2.