The oxidation states of 'P' in H P O , H P O and H P O respectively, are : 4 2 7 4 2 5 4 2 6 4 2 7 4 — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation states of 'P' in H P O , H P O and H P O respectively, are : 4 2 7 4 2 5 4 2 6 4 2 7 4 2 5 4 2 6 (A) 7, 5 and 6 (B) 5, 4 and 3 (C) 5, 3 and 4 (D) 6, 4 and 5
Answer: C) 5, 3 AND 4
💡 Solution & Explanation
H P O : 4 + 2x – 14 = 0 ⇒ 2x – 10 = 0 ⇒ 2x = 10 ⇒ x = +5 H P O : 4 + 2x – 10 = 0 ⇒ 2x – 6 = 0 ⇒ 2x = 6 ⇒ x = +3 H P O : ⇒ 4 + 2x – 12 = 0 ⇒ 2x – 8 = 0 ⇒ 2x = 8 ⇒ x = +4
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