See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the roots be a ib,a ib   then 2 2 a b 1   2 2 1 1 2 H.M 2 2a a b a ib a ib 2           From two equations we get 1 a 2  Required quadratic equation is 2 2 2 2 x 2ax a b 0 x x 1 0         Given 2 2 x log x cos sin 0             . Now comparing these two equations 2 log 1 and cos sin 1 2 and cos2 sin 1        2 0 0 0 1 2sin sin 0 sin or sin 0 2 210 ,330 ,180 Sum 720         