See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the shell hit the plane at p(x, y), the range being AP = R, as shown in the figure. The equation for the projectile’s motion is 2 2 2 gx y x tan 2u cos    …(i) Now y = R sin  …(ii) 2R  A  B R P(x, y) x = R cos  …(iii) Using equation (ii) and equation (iii) in equation (i) and simplifying 2 2 2u cos sin( ) R gcos     The maximum range is obtained by setting dR 0 d   , holding u,  and g constant. This gives cos(2 ) 0  or 2 2  