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π‘ Solution & Explanation
At 2nd equivalence point; only ο ο 2 HA ο is left. 2 3 10 a a H K K 10 ο« ο ο© οΉο½ ο΄ ο½ ο« ο» Now; ο ο 1 2 3 3 3 a a a 3 A K K K H H A ο ο« ο© οΉ ο« ο» ο© οΉ ο΄ ο΄ ο½ο« ο» ο ο 3 3 8 12 7 3 10 3 A 10 10 10 10 H A 10 ο ο ο ο ο ο© οΉ ο΄ ο΄ ο« ο»ο½ ο½ ο© οΉ ο« ο» For More Material Join: @JEEAdvanced_2025 AITS-OT-PCM(Sol.)-JEE(Main)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 13 Mathematics PART β C SECTION β A