9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate β JEE Mains Chemistry Past Papers Chemistry Question
Question
9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtained is 26.4 g. The percentage yield is β¦β¦β¦ %.
Answer: .
π‘ Solution & Explanation
NH2 NH2 Br Br Br (white ppt) 93 g of aniline produces 330 g of 2, 4, 6- tribromoaniline. Hence 9.3 g of aniline should produce 33g of 2, 4, 6-tribromoaniline. Hence percentage yield 26.4 100 80% ο΄ ο½
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