9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate — JEE Mains Chemistry Past Papers Chemistry Question
Question
9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtained is 26.4 g. The percentage yield is ……… %.
Answer: .
💡 Solution & Explanation
NH2 NH2 Br Br Br (white ppt) 93 g of aniline produces 330 g of 2, 4, 6- tribromoaniline. Hence 9.3 g of aniline should produce 33g of 2, 4, 6-tribromoaniline. Hence percentage yield 26.4 100 80% $//(1®
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes