See image β AITS & Test Series Chemistry Question
Question
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Answer: C
π‘ Solution & Explanation
3 4 Mn d ο«ο (low spin) unpaired electrons = 2 3 3 Cr d ο«ο (high spin) unpaired electrons = 3 3 6 Co d ο«ο (low spin) unpaired electrons = 0 2 6 Fe d ο«ο (high spin) unpaired electrons = 4
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