See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. S’ = 1, 15, 65, 175 S  1, 14, 50, 110 T  1, 13, 36, 60 Tn = 24n – 36 for n  3 Question Stem for Question Nos. 56 and 57 Question Stem For a recursive relation in ‘n’ we may generate nth term free from any other term i.e. purely in ‘n’. Based on this answer the following questions 56. If     2 n 1 n n 1 n a a 2 a a 0      and 0 a 1,  then   n 4 n nlim 2 a   is AITS-FT-I (Paper-2)-PCM-JEE(Advanced)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 27 Ans.