A quantity of 1 g of water on evaporation at atmospheric pressure forms 1671 cm^3 of steam. Heat of vaporization is 540 cal/g. The approximate increase in internal energy is

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Prashant Kotian · Accepted Answer

Correct answer: B. Δ H = 540 cal. W = P * Δ V = 1.013 * 10^5 N/m^2 * 1671 * 10^-6 m^3 = 169.3 Joules = 169.3 / 4.184 cal = 40.5 cal. Δ U = Δ H - W = 540 - 40.5 = 499.5 cal approx 500 cal.

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