The reaction of NiBr2 with 2 equivalent of PPh3 is CS2 at -78°C gives a red coloured diamagnetic complex [NiBr2(PPh3)2]. This transforms to a green coloured paramagnetic complex with same molecular fo

Question

The reaction of NiBr2 with 2 equivalent of PPh3 is CS2 at -78°C gives a red coloured diamagnetic complex [NiBr2(PPh3)2]. This transforms to a green coloured paramagnetic complex with same molecular formula at 25°C. The geometry and number of unpaired electrons in the coloured complex respectively are:

Prashant Kotian · Accepted Answer

Correct answer: B.      2 2 3 2 3 2 2 Ni in Ni Br PPh NiBr PPh Square planar Tetrahedral Red colour Green coloured Diamagnetic Paramagnetic            Tetrahedral splitting of Ni+2 in   2 3 2 NiBr PPh will have configuration 4 4 2 e t , thus unpaired electrons.

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