Radium (88Ra^224) decays by a series of emission of three β-particles and two α-particles. The end p — AITS & Test Series Chemistry Question
Question
Radium (88Ra^224) decays by a series of emission of three β-particles and two α-particles. The end product 'X' is
Answer: B
💡 Solution & Explanation
224 216 4 0 88 2 1 87 Ra X 2. He 3.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes