'W' g of a non-volatile electrolyte solid solute of molar mass 'M' g mol –1 when dissolved in 100 mL — JEE Mains Chemistry Past Papers Chemistry Question
Question
'W' g of a non-volatile electrolyte solid solute of molar mass 'M' g mol –1 when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg. If aqueous solution of the electrolyte boils at 375 K and Kb for water is 0.52 K kg mol –1, then the mole fraction of the electrolyte solute (x2) in the solution can be expressed as (Given : density of water = 1 g/mL and boiling point of water = 373 K) (A) .3 W M (B) 6 W 2.6 M (C) .6 M W (D) .3 W
💡 Solution & Explanation
P° = 640 mm Hg PS = 600 mm Hg P = 40 mm Hg ALLEN moles of solute = W M solute o P i.X P Again : Tb = i × kb × m 2 = i × 0.52 × W / M 100 M i 5.2 W solute 1 5.2 W X i 2 M solute 1.3 W X M