The total pressure of a mixture of non-reacting X (0.6 g) and Y (0.45 g) in a vessel is 740 mm of Hg — JEE Mains Chemistry Past Papers Chemistry Question
Question
The total pressure of a mixture of non-reacting X (0.6 g) and Y (0.45 g) in a vessel is 740 mm of Hg. The partial pressure of the gas X is ________ mm of Hg. (Nearest Integer) (Given : mole mass X = 20 and Y = 45 g mol–1) NTA (555) RESO. (555) | JEE(Main) 2023 | DATE : 31-01-2023 (SHIFT-1) | PAPER-1 | CHEMISTRY PAGE # 10
💡 Solution & Explanation
Number of moles of gas X = 6 . = 0.03 Number of moles of gas Y = 45 . = 0.01 Total number of moles = 0.03 + 0.01 = 0.04 mole Partial pressure of gas X = Mole fraction × Total pressure = . 03 . × 740 = 555
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