The half-life for a given reaction is doubled if the initial concentration of the reactant is double — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

The half-life of an n-th order reaction is related to the initial concentration by t_1/2 ∝ [A]_0^(1-n). Since t_1/2 doubles when [A]_0 is doubled: 2 ∝ 2^(1-n) => 1-n = 1 => n = 0. Thus, the reaction is of zero-order.