Question No. 1 to 3 (3 questions) (i) P + C(carbon) + Cl2 Q + CO (ii) Q + H2O R + HCl (iii) BN + H2O R + NH3 (iv) Q + LiAlH4 S + LiCl + AlCl3 (v) S + H2O R + H2 (vi) S + NaH T (P, Q, R, S and T do not

Question

Question No. 1 to 3 (3 questions)
(i) P + C(carbon) + Cl2 $\rightarrow$ Q + CO $\uparrow$
(ii) Q + H2O $\rightarrow$ R + HCl
(iii) BN + H2O $\rightarrow$ R + NH3 $\uparrow$
(iv) Q + LiAlH4 $\rightarrow$ S + LiCl + AlCl3
(v) S + H2O $\rightarrow$ R + H2 $\uparrow$
(vi) S + NaH $\rightarrow$ T
(P, Q, R, S and T do not represent their chemical symbols)

Prashant Kotian · Accepted Answer

Correct answer: A. Step 1: Borax is sodium tetraborate decahydrate (Na2B4O7.10H2O). Step 2: Adding a mineral acid (such as HCl or H2SO4) to an aqueous solution of borax results in an acid-base neutralization reaction: Na2B4O7 + 2HCl + 5H2O -> 2NaCl + 4H3BO3. Step 3: The product H3BO3 is orthoboric acid (also simply called boric acid), which precipitates out of the solution, matching option (b).

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