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HO – CH2 – CH2 – X + HC  C–Na+  A + B A & B can be (A) HO – CH2 – CH2 – C CH, NaX (B) Acetylene +AITS & Test Series Chemistry Question

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HO – CH2 – CH2 – X + HC  C–Na+  A + B A & B can be (A) HO – CH2 – CH2 – C CH, NaX (B) Acetylene + NaO – CH2 – CH2 – X (C) Ethanol + XC CNa+ (D) Ethylhalide + HOC CNa+

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