See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 Na O Na O,   2 2 2 2 1 Na O O Na O 2   It exists as 2Na and 2 2 O  So oxidation state of O is –1. For More Material Join: @JEEAdvanced_2024 AITS-CRT-I-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12 Mathematics PART – C SECTION – A