See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Molecular formula from calculation comes to be C3H6O i.e., it stands for the following compounds. O O O OH O OH OH O CH2 C H2 OH CH3 Cis and trans O Br Br 2 Br O VD×2=MM =29×2=58  58g of ether combines with 2 2×80g Br  2.9g of ether will combines with 2 80