Correct answer: 51. For 2 2 XeF : 2:1 Xe F   For 4 2 XeF : 2:10 Xe F   For 6 2 XeF : 2: 40 Xe F   Sum 1 10 40 51   

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

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Answer: 51

💡 Solution & Explanation

For 2 2 XeF : 2:1 Xe F   For 4 2 XeF : 2:10 Xe F   For 6 2 XeF : 2: 40 Xe F   Sum 1 10 40 51   

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