For the reaction started with 1 mol A2B4 (g) is A2B4 (g) → A2 (g) + 2B2 (g) The vapour densities are measured at various time of dissociation and observed value are (i) at time t = 0 min VD = 50 (ii)

Question

For the reaction started with 1 mol A2B4 (g) is

A2B4 (g) → A2 (g) + 2B2 (g)

The vapour densities are measured at various time of dissociation and observed value are
(i) at time t = 0 min VD = 50
(ii) at time t = 10 min VD = 25
(iii) at time t = 20 min VD = 20

If V.D.(A2B4) / V.D.(A2) = 5 and t100% is 40 min.

Choose the correct option(s)

Prashant Kotian · Accepted Answer

Correct answer: A,B,C. Molecular mass of 2 4 A B 100    2A 4B 2A 4B 100, 5 given 2A     A 10 A 10,B 20, 1: 2 B 20     AITS-PT-I (Paper-2)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11    2 4 2 2 A B g A g 2B g 1 2      At 10 min. V.D. = 25 Molecular mass = 50 100 50 1 2   1 2    2 1 %B by mole 100 50% 2      2 1 %A by mole 100 25% 4    At t = 20 min. 100 40 1 2  

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