1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. The work done is 3 kJ mol–1. The final temperature of the gas is _______K (Nearest integer). Given CV

Question

1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. The work done is 3 kJ mol–1. The final temperature of the gas is _______K (Nearest integer). Given CV = 20 J mol–1 K–1

Prashant Kotian · Accepted Answer

Correct answer: .. W = –q = – nCV [T2 – T1] = 3 × 103 J  –1 × 20 [T2 – 300] = 3 × 100  – (T2 – 300) = 3000  T2 = 150

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