See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

      2 2 4 2 2 2 3x 1 3x 1 x x x x 1        2 2 2 2 2 2x x 1 x x 1 2x x 1 x x 1 2 2          Equality for 2 2 2x x 1   2 x 1 x 1     2 2 4 2 0 3x 1 dx 2 2 2 0 4 x x       