A quantity of 4 g reacts with 9 * 10^23 molecules and forms gas. If the total pressure of the system β States of Matter and Gaseous State Chemistry Question
Question
A quantity of 4 g $H_2$ reacts with 9 * 10^23 $Cl_2$ molecules and forms $HCl$ gas. If the total pressure of the system after reaction is 700 mm, what is the partial pressure of $HCl$? Assume complete reaction.
Answer: D
π‘ Solution & Explanation
Moles of $H_2$ = 2 mol . Moles of $Cl_2$ = 9 * 10^23 / 6.02 * 10^23 = 1.5 mol . Reaction: $H_2$ + $Cl_2$ -> 2 $HCl$. $Cl_2$ is the limiting reagent . $HCl$ formed = 3.0 mol , $H_2$ remaining = 0.5 mol . Total moles = 3.5 . Partial pressure of $HCl$ = (3.0/3.5) * 700 = 600 mm .
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