A student has been given a compound “x” of molecular formula – C6H7N. ‘x’ is sparingly soluble in water. However, on addition of dilute mineral acid , ‘x’ becomes soluble in water. ‘x’ when treated wi

Question

A student has been given a compound “x” of molecular formula – C6H7N. ‘x’ is sparingly soluble in water. However, on addition of dilute mineral acid , ‘x’ becomes soluble in water. ‘x’ when treated with CHCl3 and KOH (alc.) ‘y’ is produced. ‘y’ has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, ‘x’ gives a compound ‘z’ which is soluble in alkali. The number of different “H” atoms present in ‘z’ is:-

(A) 5
(B) 8
(C) 4
(D) 7

Prashant Kotian · Accepted Answer

Correct answer: D. NH2 (X) CHCl3 KOH NC (Y) Unpleasant smell (X) NH2 + S–Cl O O NH–S– O O KOH(Aq) Soluble (Z) Number of different H atom in –NH–S– O O is 7. ALLEN  SECTION-B

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