See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

7 6 2 4 2 2 4 2 3 2 4 X MnO S O MnO SO           Equivalents of 4 MnO = equivalents of 2 4 SO  Moles of 4 MnO n  -factor = moles of 2 4 SO  n factor   8 3 X 4    X 6  X